3x^2-205x+1500=0

Solution for 3x^2-205x+1500=0 equation:

3x^2-205x+1500=0

a = 3; b = -205; c = +1500;
Δ = b2-4ac
Δ = -2052-4·3·1500
Δ = 24025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24025}=155$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-205)-155}{2*3}=\frac{50}{6}
=8+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-205)+155}{2*3}=\frac{360}{6}
=60
$